Prove that nCr+n−1Cr+n−2Cr+.....+rCr=n+1Cr+1.
To prove:
nCr+n−1Cr+n−2Cr+......+rCr=n+1Cr+1
nCr+n−1Cr+n−2Cr+.....+r+1Cr+rCr=n+1Cr+1
[∵nCn=n+1Cn+1]
⇒nCr+n−1Cr+n−2Cr+......+r+2Cr+(r+1Cr+r+1Cr+1)
⇒r+2Cr+1
[We know that n+1Cr+1=nCr+1+nCr]
∴nCr+n−1Cr+n−2Cr+......+r+2Cr+r+2Cr+1=n+1Cr+1
⇒nCr+n−1Cr+n−2Cr+......+r+3Cr+1=n+1Cr+1
By continuing this, we get
⇒nCr+(n−1Cr+n−1Cr+1)=n+1Cr+1
⇒nCr+nCr+1=n+1Cr+1
⇒n+1Cr+1=n+1Cr+1
L.H.S=R.H.S
[Hence proved].