The angle which is dfrac15-th- of its supplement is15-o30-o45-o60-o

Question

Toppr Admin · Accepted Answer

Let the angles be x and its supplement be y-180-x2212-xGiven - x-15y-x27F9-x-15-xD7-180-x2212-x-x27F9-5x-180-x2212-x-x27F9-6x-180-x2234-x-1806-x2234-x-30o

The angle which is ${\frac{1}{5}}^{t h}$ of its supplement is
$15^{o}$
$30^{o}$
$45^{o}$
$60^{o}$

Let the angles be $x$ and its supplement be $y = 180 - x$

Given : $x = \frac{1}{5} y$
$⟹ x = \frac{1}{5} \times (180 - x)$

$⟹ 5 x = 180 - x$

$⟹ 6 x = 180$

$∴ x = \frac{180}{6}$

$∴ x = 30^{o}$

The angle which is 15th of its supplement is15o30o45o60o

Let the angles be x and its supplement be y=180−xGiven : x=15y⟹x=15×(180−x)⟹5x=180−x⟹6x=180∴x=1806∴x=30o

The angle which is ${\frac{1}{5}}^{t h}$ of its supplement is
$15^{o}$
$30^{o}$
$45^{o}$
$60^{o}$

Let the angles be $x$ and its supplement be $y = 180 - x$

Given : $x = \frac{1}{5} y$
$⟹ x = \frac{1}{5} \times (180 - x)$

$⟹ 5 x = 180 - x$

$⟹ 6 x = 180$

$∴ x = \frac{180}{6}$

$∴ x = 30^{o}$