The binding energy per nucleon of deuteron (1H2) and helium nucleus (2He4) is 1.1MeV and 7MeV respectively. If two deuteron nuclei reacts to form a single helium nucleus, then the energy released is
13.9MeV
19.2MeV
26.9MeV
23.6MeV
A
13.9MeV
B
23.6MeV
C
26.9MeV
D
19.2MeV
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Solution
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Energy required to break 4 nucleons in the two deuterons =4×1.1MeV
Energy released in formation of 4 nucleons in the single helium nucleus =4×7MeV
Hence, total energy released =(28−4.4)MeV=23.6MeV
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