The heat of combustion of gaseous ammonia is 81 kcal/mole. How much heat will be evolved in the reaction of 34 grams of ammonia with excess amount of oxygen?

Question

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Answer 1

The molar mass of ammonia is 17 g/mol.
34 grams of ammonia corresponds to $\frac{3 4 g}{1 7 g / m o l} = 2 m o l e s$ .
The heat of combustion of gaseous ammonia is 81 kcal/mole.
During the reaction of 34 grams (2 moles) of ammonia with excess amount of oxygen, heat evolved will be $2 m o l \times 81 k c a l / m o l = 162 k c a l$ .

Answer 2

The molar mass of ammonia is 17 g/mol.
34 grams of ammonia corresponds to

\frac{3 4 g}{1 7 g / m o l} = 2 m o l e s

.
The heat of combustion of gaseous ammonia is 81 kcal/mole.
During the reaction of 34 grams (2 moles) of ammonia with excess amount of oxygen, heat evolved will be

2 m o l \times 81 k c a l / m o l = 162 k c a l

.

The heat of combustion of gaseous ammonia is 81 kcal/mole. How much heat will be evolved in the reaction of 34 grams of ammonia with excess amount of oxygen?

40.5 kcal

60.3 kg

75.8 kcal

81 kcal

162 kcal

When 6 g carbon is burnt in a sufficient amount of oxygen, the heat evolved is x KJ. The heat of combustion of carbon is

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is $- 880 k J m o l^{- 1}$ ?

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880 kJ $m o l^{- 1}$ ?

The heat of combustion is:

The heat of combustion of ethane, ethylene and hydrogen are $372.79 k c a l$ , $337.0 k c a l$ and $68.4 k c a l$ respectively. What is the heat evolved in the reaction?
$C_{2} H_{4} + H_{2} ⟶ C_{2} H_{6}$ ?

Revise with Concepts

Types of Enthalpy: Combustion

Types of Enthalpy: Atomisation

Types of Enthalpy: Solution

Types of Enthalpy: Bond

Types of Enthalpy: Lattice

The heat of combustion of gaseous ammonia is 81 kcal/mole. How much heat will be evolved in the reaction of 34 grams of ammonia with excess amount of oxygen?

40.5 kcal

60.3 kg

75.8 kcal

81 kcal

162 kcal

The molar mass of ammonia is 17 g/mol. 34 grams of ammonia corresponds to 17g/mol34g​=2moles. The heat of combustion of gaseous ammonia is 81 kcal/mole. During the reaction of 34 grams (2 moles) of ammonia with excess amount of oxygen, heat evolved will be 2mol×81kcal/mol=162kcal.

When 6 g carbon is burnt in a sufficient amount of oxygen, the heat evolved is x KJ. The heat of combustion of carbon is

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is −880 kJmol−1?

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880 kJ mol−1?

The heat of combustion is:

The heat of combustion of ethane, ethylene and hydrogen are 372.79kcal, 337.0kcal and 68.4kcal respectively. What is the heat evolved in the reaction? C2​H4​+H2​⟶C2​H6​?

Revise with Concepts

Types of Enthalpy: Combustion

Types of Enthalpy: Atomisation

Types of Enthalpy: Solution

Types of Enthalpy: Bond

Types of Enthalpy: Lattice

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is $- 880 k J m o l^{- 1}$ ?

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880 kJ $m o l^{- 1}$ ?

The heat of combustion of ethane, ethylene and hydrogen are $372.79 k c a l$ , $337.0 k c a l$ and $68.4 k c a l$ respectively. What is the heat evolved in the reaction?
$C_{2} H_{4} + H_{2} ⟶ C_{2} H_{6}$ ?