The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is :
(charge on an electron is 1.60×10−19C) :
6×1023
6×1020
7.48×1023
3.75×1020
A
3.75×1020
B
7.48×1023
C
6×1023
D
6×1020
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Solution
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Q=ne Q is the amount of electricity passed n is the number of electrons liberaed at cathode e the charge of electron i×t=ne (Q=i×t) n=i×te n=1×601.6×10−19 n=3.75×1020
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