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Question
Write in ascending order:
$$ 3 \sqrt{5} $$ and $$ 4 \sqrt{3} $$
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Solution
Verified by Toppr
$$ 3 \sqrt{5}=\sqrt{3\times3 \times 5}=\sqrt{45}, 4 \sqrt{3}=\sqrt{4\times4 \times 3}=\sqrt{48} $$
We know that, $$ 45<48 $$
$$ \therefore \sqrt{45}<\sqrt{48} \Rightarrow 3 \sqrt{5}<4 \sqrt{3} $$
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