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Question

A $220 V$ , $1000 W$ bulb is connected across a $110 V$ main supply. The power consumed will be
$1000 W$
$750 W$
$250 W$
$500 W$

A

1000 W

B

250 W

C

750 W

D

500 W

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Solution

Verified by Toppr

Power, $P = V^{2} / R$
so the resistance of bulb is $R = V^{2} / P = \frac{220^{2}}{1000} = 48.4 Ω$

Power consumed $= \frac{V_{m}^{2}}{R} = \frac{110^{2}}{48.4} = 250 W$

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