An inductor 20mH, a capacitor 50μF and a resistor 40Ω are connected in series across a source of emf V=10sin340t. The power loss in A.C. circuit is:
0.76W
0.67W
0.51W
0.89W
A
0.67W
B
0.51W
C
0.89W
D
0.76W
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Solution
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XC=1ωC=1340×50×10−6=58.8Ω
XL=ωL=340×20×10−3=6.8Ω
Z=√R2+(XC−XL)2
=√402+(58.8−6.8)2
=√4304Ω
Power, P=i2rmsR=(VrmsZ)2R
=(10/√2√4304)2×40
=50×404304≈0.51W
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An inductor 20mH, a capacitor 50μF and a resistor 40Ω are connected in series across a source of emf V=10sin340t. The power loss in A.C. circuit is:
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