As shown in the figure at 200 K and 500 atm value of compressibility factor is 2 (approx). Then the volume of the gas at this point will be:
0.09 L
0.065 L
0.657 L
0.01 L
A
0.657 L
B
0.065 L
C
0.01 L
D
0.09 L
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Solution
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The expression for the compressibility factor is z=PVmRT.
On rearranging the above, expression, Vm=z.RTP.
Substitute values in the above expression:
Vm=2×0.082×200500=0.065L.
Thus the volume of the gas is 0.065L.
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