Calculate the quantity of heat required to convert 10 kg of ice at 0∘ to water at 50∘C would be. Specific heat of water is 4200 J/kg ∘C.
4506 kJ
3360 kJ
5460 kJ
5460 J
A
4506 kJ
B
5460 J
C
3360 kJ
D
5460 kJ
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Solution
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we know that,
W=mL+mcθ
W= 10(336+ 4.2(50))= 5460 kJ
so quantity of heat required is 5460 J
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