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Parallel and Series Combination of Capacitors

Question

Obtain the equivalent capacitance of the network in given figure. For a $300 V$ supply, determine the charge across capacitor $C_{4}$ .

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Solution

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Assuming wire is joined at the point between $C_{4}$ and $C_{2}$ .
Since $C_{4}$ has the same potential on both the sides, hence no charge will flow through it.

Now for $C_{e q}$ :

$C_{2} a n d C_{3}$ are in series which is in parallel to $C_{1}$

Hence $C_{e q} = \frac{C_{2} \times C_{3}}{C_{2} + C_{3}} + C_{1}$

$C_{e q} = \frac{200 \times 200}{200 + 200} + 100 p F$

$C_{e q} = 100 + 100 p F$

$C_{e q} = 200 p F$

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