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Standard VIII
Mathematics
Algebraic Identities
Question
Show that:
(
a
−
b
)
(
a
+
b
)
+
(
b
−
c
)
(
b
+
c
)
+
(
c
−
a
)
(
c
+
a
)
=
0
Open in App
Solution
Verified by Toppr
(
a
−
b
)
(
a
+
b
)
+
(
b
−
c
)
(
b
+
c
)
+
(
c
−
a
)
(
c
+
a
)
⇒
(
a
2
−
b
2
)
+
(
b
2
−
c
2
)
+
(
c
2
−
a
2
)
=
0
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14
Similar Questions
Q1
Show that:
(
a
−
b
)
(
a
+
b
)
+
(
b
−
c
)
(
b
+
c
)
+
(
c
−
a
)
(
c
+
a
)
=
0
View Solution
Q2
Show that
(
a
−
b
)
(
a
+
b
)
+
(
b
−
c
)
(
b
+
c
)
+
(
c
−
a
)
(
c
+
a
)
=
0
View Solution
Q3
Question 5(v)
Show that:
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
View Solution
Q4
Show that the expressions
a
(
a
−
b
)
(
a
−
c
)
+
b
(
b
−
c
)
(
b
−
a
)
+
c
(
c
−
a
)
(
c
−
b
)
and
a
2
(
a
−
b
)
(
a
−
c
)
+
b
2
(
b
−
c
)
(
b
−
a
)
+
c
2
(
c
−
a
)
(
c
−
b
)
are both positive.
View Solution
Q5
(
a
−
b
)
(
a
+
b
)
+
(
b
−
c
)
(
b
+
c
)
+
(
c
−
a
)
(
c
+
a
)
=
0
View Solution