When KMnO4 acts as an oxidising agent and ultimately forms [MnO4]2−, MnO2, Mn2O3, Mn2+, then the number of electrons transferred in each case respectively is:
4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1
A
3, 5, 7, 1
B
1, 3, 4, 5
C
4, 3, 1, 5
D
1, 5, 3, 7
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Solution
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KMnO4+1e−−→[MnO4]2−
KMnO4+3e−−→MnO2
KMnO4+4e−−→Mn2O3
KMnO4+5e−−→Mn2+
Option C is correct.
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