A charge is placed at the centre of a cube. The electric flux through one face of the cube is :
Zero
Qε0
Q6ε0
Q4ε0
A
Q4ε0
B
Q6ε0
C
Qε0
D
Zero
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Solution
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As the charge at the
center of the cube, the flux through each surface is same. Using Gauss's law,
6ϕ=Qϵ0⇒ϕ=Q6ϵ0
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