An ideal gas occupying a volume of 2 dm3 and a pressure of 5 bar undergoes isothermal and irreversible expansion against external pressure of 1 bar. The final volume of the system and the work involved in the process is
10 dm3 , 1000J
8dm3, -800 J
10 dm3, -800J
10m3, -1000J
A
10 dm3, -800J
B
10m3, -1000J
C
10 dm3 , 1000J
D
8dm3, -800 J
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Solution
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Vi=2dm3,P=5bar
Vf=P1V1Pf=5×21=10dm3
Work done=−Pext(Vf−Vi)
=−(1)(10−2)
=1×105Pa×8×10−3m3
=−800J
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