Find a rational number exactly halfway between: $$\dfrac{1}{6}$$ and $$\dfrac{1}{9}$$
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As we know that exactly halfway between two rational numbers is $$\dfrac{a+b}{2}$$ Rational numbers are $$\dfrac{1}{6}$$and $$\dfrac{1}{9}$$ Here, $$a=\dfrac{1}{6}$$and $$b=\dfrac{1}{9}$$ $$\therefore \dfrac{a+b}{2}=\dfrac{\dfrac{1}{6}+\dfrac{1}{9}}{2}$$ $$=\dfrac{\dfrac{3+2}{18}}{2}$$
$$=\dfrac{5}{18\times2}$$
$$=\dfrac{5}{36}$$ Therefore, the exactly halfway between $$\dfrac{1}{6}$$and $$\dfrac{1}{9}$$is $$\dfrac{5}{36}.$$
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