lf f(x) and g(x) are two functions such that f(x)+g(x)=ex and f(x)−g(x)=e−x then I: f(x) is an even function II: g(x) is an odd function III: Both f(x) and g(x) are neither even nor odd.
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Q3
Assertion :Let f(x)=tanx and g(x)=x2 then f(x)+g(x) is neither even nor odd function. Reason: If h(x)=f(x)+g(x), then h(x) does not satisfy the condition h(−x)=h(x) and h(−x)=−h(x).
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Q4
If f(x) = x2 and g(x) = logex, then f(x) + g(x) will be
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Q5
Assertion :If f(x)=∫x0g(t)dt, where g is an even function and f(x+5)=g(x), then g(0)−g(x)=∫x0f(t)dt Reason: f is an odd function.