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Question
The equation of line $$x+y+z-1=0,4x+y-2z+2=0$$ written in the symmetrical form is :-
A
$$\frac { x+1 }{ 1 } =\frac { y-2 }{ -2 } =\dfrac { z }{ 1 } $$
B
$$\frac { \quad x }{ 1 } =\frac { \quad y }{ -2 } =\dfrac { z }{ 1 } $$
C
$$\frac { \quad x }{ 1 } =\frac { \quad y }{ -2 } =\dfrac { z+1 }{ 1 } $$
D
$$\frac { \quad x-\frac { 1 }{ 2 } }{ 1 } =\frac { \quad y-1 }{ -2 } =\dfrac { z-\dfrac { 1 }{ 2 } }{ 1 } $$
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Solution
Verified by Toppr
Correct option is A. $$\frac { x+1 }{ 1 } =\frac { y-2 }{ -2 } =\dfrac { z }{ 1 } $$
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