An electron emitted by a heated cathode and accelerated through a potential difference of 2.0 kV, enters a region with uniform magnetic field of 0.15 T. Determine the trajectory of the electron if the field (a) is transverse to its initial velocity, (b)
makes an angle of 30∘ with the initial velocity.
(a)Kinectic energy of electron = eValso, eV=12mv2
⇒v=√2eV/m−(1)
also, BeV=mv2/r
⇒r=mV/Be
using equation, (1),r=1 mm
(b)θ=30o
v1=vsinθ
r1=mvsinθ/Be=0.5mm