Distance of chord AB from the centre of a circle is 8 cm- Length of the chord AB is 12 cm- Find the diameter of the circle-

Question

Toppr Admin · Accepted Answer

Given length of chord AB-12-xA0-cm-Distance of chord from center -8cm-OC-8cm-AC-122-6-xA0-cmIn -x25B3-OAC-OA2-AC2-OC2OA2-6-2-8-2-36-64- OA-10-xA0-cm-x2234-xA0- Diameter of circle is 2-OA-20-xA0-cm-

Distance of chord $A B$ from the centre of a circle is $8 c m$ . Length of the chord $A B$ is $12 c m$ . Find the diameter of the circle.

Given length of chord $A B = 12 c m$ .
Distance of chord from center $= 8 c m$ .
$O C = 8 c m, A C = \frac{12}{2} = 6 c m$
In $△ O A C$ ,
$O A^{2} = A C^{2} + O C^{2}$
$O A^{2} = (6)^{2} + (8)^{2} = 36 + 64$
[ $O A = 10 c m$ ].
$∴$ Diameter of circle is $2 (O A) = 20 c m$ .

Distance of chord AB from the centre of a circle is 8 cm. Length of the chord AB is 12 cm. Find the diameter of the circle.

Given length of chord AB=12 cm.Distance of chord from center =8cm.OC=8cm,AC=122=6 cmIn △OAC,OA2=AC2+OC2OA2=(6)2+(8)2=36+64[ OA=10 cm].∴ Diameter of circle is 2(OA)=20 cm.

Distance of chord $A B$ from the centre of a circle is $8 c m$ . Length of the chord $A B$ is $12 c m$ . Find the diameter of the circle.

Given length of chord $A B = 12 c m$ .
Distance of chord from center $= 8 c m$ .
$O C = 8 c m, A C = \frac{12}{2} = 6 c m$
In $△ O A C$ ,
$O A^{2} = A C^{2} + O C^{2}$
$O A^{2} = (6)^{2} + (8)^{2} = 36 + 64$
[ $O A = 10 c m$ ].
$∴$ Diameter of circle is $2 (O A) = 20 c m$ .