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Standard XII
Physics
Question
If
θ
is acute and
sin
θ
=
3
/
5
then
cot
θ
=
4/5
4/3
3/4
5/4
A
3/4
B
5/4
C
4/5
D
4/3
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Solution
Verified by Toppr
cos
θ
=
1
−
sin
2
−
−
−
−
−
−
√
θ
=
1
−
9
25
−
−
−
−
−
−
√
=
4
5
cosθ=1−sin2θ=1−925=45
cot
θ
=
cos
θ
sin
θ
cotθ=cosθsinθ
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