The charges Q, +q and +q are placed at the vertices of an equilateral triangle of side l. If the net electrostatic energy of the system is zero, then Q is equal to :
−q2
+q2
−q
Zero
A
−q
B
+q2
C
Zero
D
−q2
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Solution
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E=2kQqr+kq2r=0
Q=−q2
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