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Standard VI
Maths
Question
The sum of all three-digit natural numbers which leave a remainder
2
when divided by
3
168450
168850
165840
None of these
A
168850
B
None of these
C
168450
D
165840
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Solution
Verified by Toppr
The correct option is
A
168450
First three digit number leaves remainder
2
is
101
The next being
104
,
107
,
110
,...…
Last
3
digit number
=
998
∴
101
,
104
,
…
…
998
a
=
101
,
d
=
3
n
t
h
term
⇒
998
=
a
+
(
n
−
1
)
d
998
=
101
+
(
n
−
1
)
3
(
n
−
1
)
/
3
=
/
897
299
n
=
300
.
S
n
=
300
2
(
2
(
101
)
+
(
300
−
1
)
3
)
=
300
2
(
202
+
897
)
=
164850
.
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