V0 is the potential at the origin in an electric field. →E=Ex→i−Ey→j. The potential at the point (x,y) is:
V0−xEx+yEy
V0+xEx+yEy
√x2+y2√E2x+E2y−V0
xEx+yEy−V0
A
V0+xEx+yEy
B
V0−xEx+yEy
C
xEx+yEy−V0
D
√x2+y2√E2x+E2y−V0
Open in App
Solution
Verified by Toppr
We know V(x1)−V(x2)=∫x2x1Edx. Now potential change in x direction Vx(x)−Vx(o)=∫oxExdx=−Exx. Vx(x)=Vx(o)−Exx Potential change in y direction Vy(y)−Vy(o)=∫oy(−Ey)dy=+Eyy Vy(y)=Vy(o)+Eyy Now total potential at (x,y) =Vx+Vy =Vx(o)−Exx+Vy(o)+Eyy =Vo−xEx+yEy
Was this answer helpful?
0
Similar Questions
Q1
V0 is the potential at the origin in an electric field. →E=Ex→i−Ey→j. The potential at the point (x,y) is:
View Solution
Q2
If V0 be the potential at origin in an electric field →E=Ex^j+Ey^j, then the potential at point P(x,y) is
View Solution
Q3
Assume that an electric field →E=30x2^i exists in space. Then the potential difference VA−V0, where V0 is the potential at the origin and VA the potential at x=2m, is :
View Solution
Q4
Assume that and electric field →E=30x2i exists is space. Then the potential difference VA–V0 is: (where V0 is the potential at the origin and VA is the potential at x = 2m)
View Solution
Q5
A cube made of insulating material has uniform charge distribution throughout its volume. Taking the electric potential due to this charged cube at infinity to be zero, the potential at the center is found to be Vo. The potential at one of its corners is