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11th
Chemistry
Equilibrium
Homogeneous and Heterogeneous Equilibria
Homogeneous and Heterogeneous Equilibria
Equilibrium
Chemistry
Class 11
Overview
Study Materials
Solubility Equilibria: Solubility Product Equilibrium Constant (Ksp), Videos
Quick summary
with Stories
Classification of Chemical Equilibrium
2 mins read
Revise
with Concepts
Homogeneous Equilibrium
Example
Definitions
Formulaes
Heterogeneous Equilibrium
Example
Definitions
Formulaes
Related questions
If
A
g
+
+
2
N
H
3
⇌
A
g
(
N
H
3
)
2
+
;
K
1
=
1
.
8
×
1
0
7
A
g
+
C
l
−
⇌
A
g
C
l
;
K
2
=
5
.
6
×
1
0
9
Then for
A
g
C
l
+
2
N
H
3
⇌
[
A
g
(
N
H
3
)
2
]
+
+
C
l
−
Equilibrium constant will be
View solution
When sulphur (in the form of
S
8
) is heated at temperature T, at equilibrium, the pressure of
S
8
falls by
3
0
%
from 1.0 atm, because
S
8
(
g
)
is partially converted into
S
2
(
g
)
. Find the value of
K
p
for this reaction.
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N
2
O
4
is 25% dissociated at
3
7
o
C
and one atmosphere pressure. Calculate
K
p
and the percentage dissociation at
0
.
1
atmosphere and
3
7
o
C
.
View solution
Unit of equilibrium constant is:
View solution
The equilibrium constant can be related with energy change as
d
T
d
ln
K
c
=
Δ
H
/
R
T
2
.
If true enter 1, if false enter 0.
View solution
We know that the relationship between
K
c
and
K
p
is
K
p
=
K
c
(
R
T
)
Δ
n
What would be the value of
Δ
n
for the reaction,
N
H
4
C
l
(
s
)
⇋
N
H
3
(
g
)
+
H
C
l
(
g
)
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The volume of container in which gas is heated is :
View solution
For the reaction :
2
N
O
2
(
g
)
⇌
2
N
O
(
g
)
+
O
2
(
g
)
,
(
K
c
=
1
.
8
×
1
0
−
6
at
1
8
4
o
C
)
(
R
=
0
.
0
8
2
L
a
t
m
/
(
m
o
l
.
K
)
When
K
p
and
K
c
are compared at
1
8
4
o
C
, it is found that
View solution
For the reaction
C
O
(
g
)
+
C
l
2
(
g
)
⇌
C
O
C
l
2
(
g
)
,
K
p
/
K
c
equal to
View solution
The equilibrium constant for the reaction
H
2
(
g
(
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is 50 at 500 K. In presence of suitable catalyst, equilibrium is attained four times faster. The equilibrium constant of the reaction at 500 K in the presence of catalyst should be-
View solution
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More topics
Equilibrium: Basic Definitions
Equilibrium in Physical Processes
Equilibrium in Chemical Processes
Law of Chemical Equilibrium and Equilibrium Constant
Homogeneous and Heterogeneous Equilibria
Applications of Equilibrium Constants
Relationship between Equilibrium Constant, Reaction Quotient and Gibbs Energy
Factors Affecting Equilibria
Ionic Equilibrium in Solution
Acids, Bases and Salts
Ionization of Acids and Bases
More About Ionization of Acids and Bases
Hydrolysis of Salts and the pH of their Solutions
Buffer Solutions
Solubility Equilibria
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Learning videos
8,000+
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