A capacitor stores 40μC charge when connected across a battery. When the gap between the plates is filled with a dielectric a charge of 80μC flows through the battery. The dielectric constant of dielectric inserted is?
2
3
1
4
A
2
B
3
C
4
D
1
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Solution
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∵C0=ε0Ad and C=εAd=Kε0Ad So, q0=C0V=εAdV and q=CV=Kε0AdV ∴qq0=K Given q0=40μC On inserting a dielectric, an additional charge of 80μC also flows through the battery. So, total charge =q0+80=40+80=120μC ∴K=qq0=12040=3.
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