A charge q is placed at the centre of a cubical box of side a with top open. The flux of electric field through the surface of the cubical box is:
q/6ε0
q/ε0
zero
5q/6ε0
A
q/ε0
B
zero
C
q/6ε0
D
5q/6ε0
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Solution
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because charge is placed at the centre of the box, by symmetry we can say that, ϕeachface=16ϕtotal
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