maths

A military tent is made as a combination of right circular and right circular cone on top.

Given:

Total height of tent = h = 8.25 m

Base diameter of tent = 30 m, then

Base radius of tent = r = 30/2 m = 15 m

Height of right circular cylinder = 5.5 m

Base radius of cone = 15 m

Base radius of cone = 15 m

Let slant height of cone = I m

Now,

Curved surface area of right circular part of tent = $2πrh$

and

Height of conical part = total height of tent - height of cyclindrical part

height of cone = 8.25 = 5.5 = 2.75 m

$l_{2}=h_{2}+r_{2}$

$=2.75_{2}+15_{2}$

= 232.5625

or I = 15.25 m

Curved surface area of conical part of the tent = $πrl$

Total surface area of the tent = Curved surface area of cylindrical part + curved surface area of conical part

Total surface area of tent = $2πrh+πrl$

$=πr(2h+l)$

= $722 ×15×(2×5+15.25)$

= 1237.5

Total surface area of tent is $1237.5m_{2}$

Length of canvas used = 1.5 m

Length of canvas used x breadth of canvas used = Total surface area of tent

length of canvas used = 1237.5 /1.5 = 825

Answer verified by Toppr

View solution

View solution

View solution

View solution

View solution

View solution

View solution

(i) The cost of canvas required for making the tent, if the canvas cost Rs. $70$ per $1$ sq. m.

(i) If every person requires $3.5$ m$_{2}$ air, how many can be seated in that tent.

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View solution

View more

Create custom Assignments

Customize assignments and download PDF’s