A mixture of 40 liters of milk and water contains 10% water. How much water should be added to this so that water may be 20% in the new mixture ?

Question

A mixture of 40 liters of milk and water contains 10 - water- How much water must be added to 20 - water in the new mixture-3 liters4 litres5 litres6 litres

Toppr Admin · Accepted Answer

10- of water is present in 40 liters of milk-xA0-Hence milk -x2192- 36l and water -x2192- 4l4-x40-x-15-xA0- -20- -15-20-5x-40-x4x-20x-55 litres of water must be added

A mixture of $40$ liters of milk and water contains $10$ $%$ water. How much water must be added to make $20$ $%$ water in the new mixture?
$3$ liters
$4$ litres
$5$ litres
$6$ litres

$10$ % of water is present in $40$ liters of milk

Hence milk $\to$ $36 l$ and water $\to$ $4 l$

$\frac{4 + x}{40 + x} = \frac{1}{5}$ ( $20$ % $= \frac{1}{5}$ )

$20 + 5 x = 40 + x$

$4 x = 20$

$x = 5$

$5$ litres of water must be added

A mixture of 40 liters of milk and water contains 10 % water. How much water must be added to make 20 % water in the new mixture?3 liters4 litres5 litres6 litres

10% of water is present in 40 liters of milk Hence milk → 36l and water → 4l4+x40+x=15 (20% =15)20+5x=40+x4x=20x=55 litres of water must be added

A mixture of $40$ liters of milk and water contains $10$ $%$ water. How much water must be added to make $20$ $%$ water in the new mixture?
$3$ liters
$4$ litres
$5$ litres
$6$ litres

$10$ % of water is present in $40$ liters of milk

Hence milk $\to$ $36 l$ and water $\to$ $4 l$

$\frac{4 + x}{40 + x} = \frac{1}{5}$ ( $20$ % $= \frac{1}{5}$ )

$20 + 5 x = 40 + x$

$4 x = 20$

$x = 5$

$5$ litres of water must be added