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Question

BP = EP, where P is the point of intersection of BC and ED produced.

Solution
Verified by Toppr

On ABC and AED,
AB=AE
ABC=AED
and BC=ED
ABCAED (by SAS congruence rule.)
AC=AD(1) (By CPCT.)
and BCA=EDA(2) (By CPCT.)
In CAD,AC=AD(from(1))
So, from base angle theorem,
ACD=ADC(3)
BCD=BCA+ACD(4)
and EDC=angleEDA+ADCEDC=BCA+ACD(5)BCD=EDC

1038264_194450_ans_a0a2c5b817aa408da9b22970234aa4e8.png

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