maths

$AB=AE$

$∠ABC=∠AED$

and $BC=ED$

$∴△ABC≅△AED$ (by SAS congruence rule.)

$AC=AD⟶(1)$ (By CPCT.)

and $∠BCA=∠EDA⟶(2)$ (By CPCT.)

In $△CAD,AC=AD⟶(from(1))$

So, from base angle theorem,

$∠ACD=∠ADC⟶(3)$

$∠BCD=∠BCA+∠ACD⟶(4)$

and $∠EDC=angleEDA+∠ADC∴∠EDC=∠BCA+∠ACD⟶(5)⟹∠BCD=∠EDC$

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If so, state the other pairs of corresponding parts.

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$ΔABX≅ΔQCX$.

$DC=CQ=QP$.

is that True or False?

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$∠CAD=∠BAE$

**State whether the above statement is true or false.**

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$△ABP≅triangleACP$

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