maths

As per given the thickness of disc =$5mm=105 cm=0.5cm$

Radius of disc =3.5 cm

Cuvered surface area of cylinder =462 sq cm

$∴2πr=462cm_{2}$.......................................(1)

Let number of discs are x

The height of cylinder =h= $thicknessofdisc×numberofdiscs=0.5x$

$∴2πr=2×722 ×3.5×05x$............................(2)

From equation (1) and (2) we get

$∴2πr=2×722 ×3.5×05x=462$

$→x=2×22×3.5×0.5462×7 =42$ discs

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