For the reaction 2NO2(g)+12O2(g)⇌N2O5(g). If the equilibrium constant is Kp, then the equilibrium constant for the reaction 2N2O5(g)⇌4NO2(g)+O2(g) would be:
K2p
2Kp
1K2p
1√Kp
A
1√Kp
B
2Kp
C
K2p
D
1K2p
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Solution
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By writing the equation for the reverse reactionN2O5(g)→2NO2(g)+12O2(g)
New pressure constant Kp′ for this reaction
Kp′=1Kp
K′p=[NO2]2[O2]12[N2O5]
Thus pressure constant for the reaction,
2N2O5(g)⇌4NO2(g)+O2(g)
K′′p=[NO2]4[O2][N2O5]2
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