maths

We know, volume of the cone $V=31 πr_{2}h$

and curved surface $C=πrl=πrh_{2}+r_{2} $

Then, $3πVh_{3}−C_{2}h_{2}+9V_{2}$

$⟹$ $3π$ $(31 πr_{2}h)$ $h_{3}−$ $(πrh_{2}+r_{2} )h_{2}+9$ $(31 πr_{2}h)_{2}$

$⟹$ $π_{2}r_{2}h_{4}$ $−π_{2}r_{2}h_{4}$ $−π_{2}r_{2}h_{4}$ $+π_{2}r_{2}h_{4}$ $=0$.

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If the radius of the base of a right circular cone is $3r$ and its height is equal to the radius of the base, then its volume is?

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Base diameter $=28cm$, slant height $=50cm$

Base diameter $=70cm$, height $8.4cm$

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