Solution -
Let (x,y) be the center of the circle
All points (2,0),(0,1),(4,5),(0,C) are equidistant
from the circle
Let us find out x,y by making two equations
(x−2)2+y2=x2+(y−1)2...(1)
(x−2)2+y2=(x−4)2+(y−5)2...(2)
From (1)
4−ax=1−2y...(3)
From (2)
4x=37−10y...(4)
Afters solving
x=136,y=176
equating the distance of different point from center
(136−2)2+(176)2=(136−0)2+(176−c)2
136+28936=16936+(17−6c2)36
121=(17−6c)2
17−6c=±11
C=1,143
Option B,C are correct