In △OAC, we have ∠OAC+∠OCA+∠AOC=180o (Angle sum property) ∠OAC+60o+20o=180o ∠OAC=180o− (60o+20o) =180o−80o=100o As △AOC≅△ODB Therefore, ∠OAC=∠OBD (By CPCT) So, ∠OBD=100o
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Similar Questions
Q1
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Q2
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Q3
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Q5
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