If two medians of a triangle are equal, then the triangle is
Equilateral
Isosceles
Scalene
Right-angled
A
Equilateral
B
Isosceles
C
Scalene
D
Right-angled
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Solution
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If BE=CF and G is centroid, then GC=23FC=23BE=BG FG=13FC=13BE=EG ∠G=∠G ∴ΔFGB≅ΔEGC (By SAS postulate) ∴FB=EC or12AB=12ACorAB=AC Therefore, ΔABC is isosceles.
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