Question

(ii) $$\left( \frac { 22 }{ 7 } +\frac { 36 }{ 5 } \right) X\frac { 6 }{ 7 }$$

Answer 1

$$\left( \dfrac { 22 }{ 7 } +\dfrac { 36 }{ 5 } \right) \times\dfrac { 6 }{ 7 }$$

$$=\left( \dfrac { 22\times5+36\times7 }{ 7\times5 } \right) \times\dfrac { 6 }{ 7 } $$

$$\dfrac { 110+252 }{ 35 } \times\dfrac { 6 }{ 7 } =\dfrac { 362 }{ 35 } \times\dfrac { 6 }{ 7 } =\dfrac { 2172 }{ 235 } $$