maths

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ABCD is a square; X is the mid-point of AB and Y the mid-point of BC.Hence, DX is perpendicular to AY.

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$ar.(ΔAGB)=ar.(ΔAGC)=ar(ΔBGC)=31 ar(ΔABC)$

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(i) the triangles are congruent.

(ii) the triangles are not congruent

What can you say about their perimeters?

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$△ABP≅triangleACP$

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Is $∠BCD=90_{∘}$. ?

If true then enter 1 else if False enter 0

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