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"In \$ \\triangle A B C \$, medians \$ B D \$ and \$ C E \$ are perpendicular to each other at point \$ P . \$ If \$ B D = 18 , C E = 15 \$\nthen find \$ \\frac { \\operatorname { ar } ( A E P D ) } { 10 } \$."

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"In \\( \\triangle A B C \\), medians \\( B D \\) and \\( C E \\) are perpendicular to each other at point \\( P . \\) If \\( B D = 18 , C E = 15 \\)\nthen find \\( \\frac { \\operatorname { ar } ( A E P D ) } { 10 } \\)."

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Related questions

Referring to the given figure, $E$ is the center of the circle and $A C$ and $B D$ are diameters. If $Δ A E B ≅ Δ D E C$ , then the congruence theorem used to prove this is:

In the above figure $Δ$ ABD $≅$ $Δ$ ACD,If $∠$ BDC = $11 0^{0}$ and $∠$ DAC = $3 0^{0}$ then the measure of angle DBA is:

Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, $∠ D X A = ∠ A Y B$
If the above statement is true then mention answer as 1, else mention 0 if false

In $Δ A B C$ , AD is the median and DE is parallel to BA, where E is a point in AC. Hence, BE is also a median.
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In the given figure, the point P bisects AB and DC. Prove that $Δ$ APC $≅ Δ$ BPD.

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"In \\( \\triangle A B C \\), medians \\( B D \\) and \\( C E \\) are perpendicular to each other at point \\( P . \\) If \\( B D = 18 , C E = 15 \\)\nthen find \\( \\frac { \\operatorname { ar } ( A E P D ) } { 10 } \\)."

Answer

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Take Toppr Scholastic Test for Aptitude and Reasoning

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Referring to the given figure, $E$ is the center of the circle and $A C$ and $B D$ are diameters. If $Δ A E B ≅ Δ D E C$ , then the congruence theorem used to prove this is:

In the above figure $Δ$ ABD $≅$ $Δ$ ACD,If $∠$ BDC = $11 0^{0}$ and $∠$ DAC = $3 0^{0}$ then the measure of angle DBA is:

Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, $∠ D X A = ∠ A Y B$
If the above statement is true then mention answer as 1, else mention 0 if false

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In the given figure, the point P bisects AB and DC. Prove that $Δ$ APC $≅ Δ$ BPD.

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