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Standard IX
Mathematics
Natural Numbers
Question
Solve
a
3
−
27
5
a
2
−
16
a
+
3
÷
a
2
+
3
a
+
a
25
a
2
−
1
Open in App
Solution
Verified by Toppr
a
3
−
27
5
a
2
−
16
a
+
3
÷
a
2
+
3
a
+
2
25
a
2
−
1
=
a
3
−
27
5
a
2
−
16
a
+
3
×
25
a
2
−
1
a
2
+
3
a
+
9
=
(
a
−
3
)
(
a
2
+
3
a
+
9
)
(
5
a
−
1
)
(
a
−
3
)
×
(
5
a
+
1
)
(
5
a
−
1
)
(
a
2
+
3
a
+
9
)
=
(
5
a
+
1
)
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Similar Questions
Q1
Solve
a
3
−
27
5
a
2
−
16
a
+
3
÷
a
2
+
3
a
+
a
25
a
2
−
1
View Solution
Q2
Simplify:
a
3
−
27
5
a
2
−
16
a
+
3
÷
a
2
+
3
a
+
9
25
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Q3
Simplify
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27
25
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5
a
+
1
÷
a
2
+
3
a
+
9
125
a
3
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Q4
Simplify :
a
3
−
27
5
a
2
−
16
a
+
3
÷
a
2
+
3
a
+
9
25
a
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Q5
Solve :
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View Solution