maths

$AB=AC$ [Given]

$∠ABC=∠ACB......(1)$ [Angles opposite to equal sides of a trinagle are equal]

Also, $21 AB=21 AC$

$BE=CD.......(2)$ [Halves of equals are equal]

Since BD and CE are two medians

Now,

In $△BDC$ and $△CEB$

From (1) $∠BCD=∠CBE$

From (2) $BE=CD$

$BC=CB$ [Common]

$∴△BDC≅△CEB$ [SAS Congruence rule]

$∴BD=CE$ [By CPCT]

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(i) the triangles are congruent.

(ii) the triangles are not congruent

What can you say about their perimeters?

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Which statement must be true?

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The given figure shows a triangle ABC in which AB = AC. M is a point on AB and N is a point on AC such that BM = CN.

Hence,AM = AN

State true or false.

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BD = CE

State whether the above statement is true or false.

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