maths

Let r m be the radius of the base h m be the height and l m be the slant height of the cone Then

Circumference=44 metres

$⇒2πr=44⇒2×722 ×r=44⇒r=7$

metres It is given that h=10 metres

$∴l_{2}=r_{2}+h_{2}⇒l=r_{2}+h_{2} $

$=49+100 =149 =12.2m$

Now surface area of the tent $=πrl$

$722 ×7×12.2m_{2}=268.4m_{2}$

$∴$ Area of the canvas used $=268.4m_{2}$

It is given that the width of the canvas is 2 m

$∴$ Length of the canvas used=$=widtharea =2268.4 =134.2m$

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