The displacement-time graph of a particle moving along a straight line is shown in the figure. The acceleration of the particle is:
0ms−2
4ms−2
8ms−2
12ms−2
A
0ms−2
B
8ms−2
C
4ms−2
D
12ms−2
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Solution
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x=4t2 v=dxdt=8t Hence, velocity-time graph is a straight line having slope i.e. tanθ=8 a=dvdt=8m/s2 Hence, acceleration is constant throughout and is equal to 8m/s2.
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