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Standard XII
Chemistry
Nernst Equation
Question
The half cell involving the reaction
C
r
2
O
2
−
7
(
a
q
)
+
14
H
+
(
a
q
)
+
6
e
→
2
C
r
3
+
(
a
q
)
+
7
H
2
O
can be represented as :
P
t
,
H
+
(
a
q
)
,
C
r
2
O
2
−
7
(
a
q
)
P
t
,
H
+
,
C
r
3
+
(
a
q
)
P
t
,
H
2
,
C
r
2
O
2
−
7
(
a
q
)
,
C
r
3
+
(
a
q
)
P
t
,
H
+
,
C
r
2
O
2
−
7
(
a
q
)
,
C
r
3
+
(
a
q
)
A
P
t
,
H
+
,
C
r
2
O
2
−
7
(
a
q
)
,
C
r
3
+
(
a
q
)
B
P
t
,
H
+
(
a
q
)
,
C
r
2
O
2
−
7
(
a
q
)
C
P
t
,
H
+
,
C
r
3
+
(
a
q
)
D
P
t
,
H
2
,
C
r
2
O
2
−
7
(
a
q
)
,
C
r
3
+
(
a
q
)
Open in App
Solution
Verified by Toppr
It is reduction half cell of
C
r
2
O
−
2
7
and is represented as:
(
P
t
)
,
H
+
,
C
r
2
O
2
−
7
(
a
q
)
,
C
r
3
+
(
a
q
)
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Similar Questions
Q1
The half cell involving the reaction
C
r
2
O
2
−
7
(
a
q
)
+
14
H
+
(
a
q
)
+
6
e
→
2
C
r
3
+
(
a
q
)
+
7
H
2
O
can be represented as :
View Solution
Q2
The electrode with reaction :
C
r
2
O
2
−
7
(
a
q
)
+
14
H
⊕
(
a
q
)
+
6
e
−
→
2
C
r
3
+
(
a
q
)
+
7
H
2
O
can be represented as:
View Solution
Q3
The oxidation half reaction for following reaction is
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7
2-
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Q4
Write balanced net ionic equation for the following reactions in acidic solution.
S
2
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2
−
(
a
q
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+
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O
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2
−
(
a
q
)
→
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2
−
(
a
q
)
+
C
r
3
+
(
a
q
)
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Q5
Balance the following chemical equation:
C
r
2
O
2
−
7
(
a
q
)
+
S
O
2
−
3
(
a
q
)
→
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+
(
a
q
)
+
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(
a
q
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View Solution