The particle is executing S-H-M- on a line 4 cm long- If its velocity mean position is 12 cm-sec- its frequency in Hz will be -dfrac-2pi-3-dfrac-3-2pi-dfrac-pi-3-dfrac-3-pi-

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Toppr Admin · Accepted Answer

Amplitude-2cm-AVelocity of SHM at mean position-A-x3C9-x21D2-12-A-x3C9-12-2-xD7-x3C9-x21D2-x3C9-6Frequency -x3C9-2-x3C0-x21D2-f-62-x3C0-3-x3C0-x21D2-f-3-x3C0-Option D-

The particle is executing $S . H . M .$ on a line $4 c m$ long. If its velocity at mean position is $12 c m / s e c$ , its frequency in $H z$ will be :
$\frac{2 π}{3}$
$\frac{3}{2 π}$
$\frac{π}{3}$
$\frac{3}{π}$

Amplitude $= 2 c m = A$
Velocity of SHM at mean position
$= A ω$
$\Rightarrow 12 = A ω$

$12 = 2 \times ω \Rightarrow ω = 6$

Frequency $= \frac{ω}{2 π}$

$\Rightarrow f = \frac{6}{2 π} = \frac{3}{π}$

$\Rightarrow f = \frac{3}{π}$
Option D.

The particle is executing S.H.M. on a line 4 cm long. If its velocity at mean position is 12 cm/sec, its frequency in Hz will be :2π332ππ33π

Amplitude=2cm=AVelocity of SHM at mean position=Aω⇒12=Aω12=2×ω⇒ω=6Frequency =ω2π⇒f=62π=3π⇒f=3πOption D.

The particle is executing $S . H . M .$ on a line $4 c m$ long. If its velocity at mean position is $12 c m / s e c$ , its frequency in $H z$ will be :
$\frac{2 π}{3}$
$\frac{3}{2 π}$
$\frac{π}{3}$
$\frac{3}{π}$

Amplitude $= 2 c m = A$
Velocity of SHM at mean position
$= A ω$
$\Rightarrow 12 = A ω$

$12 = 2 \times ω \Rightarrow ω = 6$

Frequency $= \frac{ω}{2 π}$

$\Rightarrow f = \frac{6}{2 π} = \frac{3}{π}$

$\Rightarrow f = \frac{3}{π}$
Option D.