the perpendiculars from B and C to the opposite sides are equal. If the above statement is true then mention answer as 1, else mention 0 if false
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Given, △ABC, ∠B=∠CBE⊥AC and CF⊥AB To prove: BE=CF In △s BEC and BFC ∠BEC=∠BFC=90 (Given) BC = BC (common) ∠ABC=∠ACB (Given) Thus, △s BEC ≅ CFB (AAS Congruency) Hence, BE=CF
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