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Let the radius be 5x height be 12x

volume = 2512$cm_{3}$

volume of right circular cone =$31 πr_{2}h$

$2512=31 ×722 ×5x×5x×12x$

$⇒x_{3}=8$

$⇒x=2$

So radius = 10 cm height =24 cm

CSA=$πrl=πrπ_{2}h_{2} $

$722 ×10100+24_{2} =816.4$

$TSA=CSA+πr_{2}$

=816.4+$722 ×10×10=1130.559$

=1130.56$cm_{2}$

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