maths

Let $t$ is thickness of the cylinder

$r_{1}$ is outer radius of the cylinder

$r_{2}$ is inner radius of the cylinder

$h$ is height of the cylinder

$∴t=2cm$

$r_{1}=14cm$

$h=70cm$

Now, inner radius is calculated as,

$r_{2}=r_{1}−t$

$∴r_{2}=14−2=12cm$

1) Volume of the hollow cylinder is given by,

$V=c/sarea×heightofcylinder$

$∴V=(πr_{1}_{2}−πr_{2}_{2})×h$

$∴V=π(14_{2}−12_{2})×70$

$∴V=722 (196−144)×70$

$∴V=22×52×10$

$∴V=11440cm_{3}$

2) Given wright of the metal, $ρ=8cm_{3}g $

Let $m$ = mass of the cylinder

$∴ρ=Vm $

$∴8=11440m $

$∴m=8×11440$

$∴m=91520gm$

$∴m=91.520kg$

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Height $=10$ ft.

Radius $=2$ ft.

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