Consider refraction of light from first surface of L1,
1.4v1−1−∞=1.4−120
Consider refraction of light from second surface of L1,
1v2−1.4v1=1−1.4−∞
Hence, v2=50cm
Now this image is obtained after refraction from lens L1 and lies on the principal axis of L1.
This image gets refracted from L2 for which it is at a height of
4.5mm.
Consider refraction of light from first surface of L2,
1.5v3−1v2=1.5−1−∞
Consider refraction of light from second surface of L2,
1v4−1.5v3=1−1.5−20
⟹v4=2009cm
Height of final image =M×4.5mm=2mm
This is the height of object above principal axis of L2.
Hence the final image is 4.5mm−2mm=2.5mm below principle axis of
L1.