maths

Height of the cone, $h=24cm$

Volume of the cone $=1212cm_{3}$

$∴πr_{2}h=1212cm_{3}$

$⇒31 ×722 ×r_{2}×24=1212$

$⇒r_{2}=22×81212×7 =48.2$

$⇒r=7cm$ (Approx)

Now,

$I_{2}=r_{2}+h_{2}$

$⇒I_{2}=(7)_{2}+(24)_{2}$

$⇒I_{2}=49+573=625$

$⇒I=625 =25cm$ (Approx)

$∴$ Surface area of the cone $=πrI=722 ×7×25=550cm_{2}$ (approx)

Thus, the surface area of the cone is approximately $500cm_{2}$

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